Hacking Machines Clarification
In a 2-player game, with both players Nearby
—which is in the Routine
condition—they attempt to hack it.
Player 1 = Jonas
Player 2 = Veronica
The Paarhufer has 2 Firewalls.
So, they need to spend at least 2-time to initiate the first hack. (Can they spend more time to get more dice?)
Both Jonas and Veronica spend 1-time
each to initiate a Hack
on the Machine.
The first firewall is Green Lightning Bolt over Yellow Fist
. Green is Veronica's strength...
So, if they each spent 1-time, plus Veronica's Strength, the total dice being rolled = 3, right? (1 dice for each time + 1 for Veronica's strength)
So, if they each spent 2-time, plus Veronica's Strength, the total dice being rolled = 5.
Veronica rolls her dice and turns up a 6.
Jonas rolls his and gets a 3, but it's still a group success.
Now, they attack the 2nd/Last Firewall.
Do they need to spend 1-time again to hack? Or do they need to spend 2-time for every Firewall? And, thus, hacking the Watchdogs would require 3-time for every hack attempt?
Is that how this works?
Looking at the Summary Sheet
— there are actually TWO actions that need to be taken to Hack a Firewall:
2.1 = First resolve the Firewall effect, then roll to Hack it.
What is the difference?
Maybe the first action requires Veronica to roll 5 dice (the first firewall is green, and that's her strength) and Jonas rolls 3.
Then, if either of them rolls a 6, they now have the option to Hack
So, what do they roll to hack — is it as I described above? One dice for each Time
spent ?? Or is Hacking
simply moving the Hack token to the next Firewall or...?