On Discord we've just been discussing the table which shows the probability of getting a success which appears in the YZE games. It seems to be the same table in all the D6 pool based games.

The chance to get at least one success should be one minus (the chance to not get any successes).

The chance to get no successes is 5/6 raised to the power of the number of dice rolled [(5/6)^N, where N is the number of dice rolled]. One minus this matches the probabilities in the first, initial roll, column.

The chance to have no successes after the push is this probability squared, which should be the same as the probability for an initial roll with twixce as many dice. ((5/6)^N)^2 = (5/6)^2N

So the chance for at least one success after a push should be the same as the chance for a success on an initial oll with twice as many dice and I can't see why the "with push" probabilities are all slightly lower than this?

Anyone got any insight into how the book probabilities were calculated?